Maths

A building, B, is observed from two points P and Q which are 250 m apart. The angles PQB and QPB are found to be 67 degrees and 73 degrees respectively. What is the distance, to the nearest metre, of P from the building?

asked by Jay
  1. angle B is 180-67-73 = 40°
    Now, using the law of sines

    250/sin40° = PB/sin67°

    posted by Steve

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