i did re post it because i hd miss spells
the side of a triangle are 3x+2,6x-1, and 7-x. express the perimeter of the triangle in terms of x.
same problem. Just add up the three values
3x+2
6x-1
-x+7
------
8x+8
To express the perimeter of the triangle in terms of x, we need to add up the lengths of all three sides.
Given that the lengths of the sides are 3x+2, 6x-1, and 7-x, we can add them together to get the perimeter:
Perimeter = (3x+2) + (6x-1) + (7-x)
Simplifying the expression, we combine like terms:
Perimeter = 3x + 2 + 6x - 1 + 7 - x
Now, we can simplify further by combining the x terms:
Perimeter = (3x + 6x - x) + (2 - 1 + 7)
Simplifying once again, we combine like terms:
Perimeter = 8x + 8
So, the perimeter of the triangle in terms of x is 8x + 8.
To express the perimeter of the triangle in terms of x, we need to add up the lengths of all three sides of the triangle.
The sides of the triangle are given as 3x + 2, 6x - 1, and 7 - x.
Perimeter = (3x + 2) + (6x - 1) + (7 - x)
Now we can simplify and combine like terms:
Perimeter = 3x + 2 + 6x - 1 + 7 - x
Perimeter = (3x + 6x - x) + (2 - 1 + 7)
Simplifying further:
Perimeter = 8x + 8
Therefore, the perimeter of the triangle in terms of x is 8x + 8.