How would you write an ionic equation for: NH2SO3H + NaOH —> NaNH2SO3 + H2O?
Is it simply H+ + OH- —> H2O?
yes
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To write an ionic equation for the given chemical reaction NH2SO3H + NaOH -> NaNH2SO3 + H2O, we need to first identify the species that dissociate into ions in solution. These are typically strong electrolytes like acids, bases, and ionic compounds.
In this reaction, NH2SO3H (an acid) and NaOH (a base) are undergoing a neutralization reaction. When acids react with bases, they form water and a salt.
The neutralization reaction can be written in molecular form as:
NH2SO3H + NaOH -> NaNH2SO3 + H2O
To write the ionic equation, we need to break down the reactants and products into their respective ions:
NH2SO3H (acid) -> NH2SO3H(aq) -> NH2SO3- + H+
NaOH (base) -> Na+ + OH-
NaNH2SO3 (salt) -> Na+ + NH2SO3-
H2O (water) -> H2O
Now, we can write the balanced ionic equation by canceling out the spectator ions (ions that appear on both sides of the equation):
H+ + OH- -> H2O
Therefore, your suggested ionic equation H+ + OH- -> H2O is correct for the given neutralization reaction NH2SO3H + NaOH -> NaNH2SO3 + H2O.