Two blocks of mass m1 = 320 g and m2 = 725 g are pushed by a force. The coefficient of kinetic friction between each block and the ground is 0.4. The blocks move together (with one pushing the other) with an acceleration of 225 cm/s2. What is the value of the applied force in Newtons?
M*g = (0.320+0.725) * 9.8 = 10.24 N.
Fk = u*Fn = (0.4+0.4)10.24 = 8.19 N. = Force of kinetic friction.
Fap-Fk = M*a.
Fap-8.19 = ((0.320+0.725)*2.25
Fap = ?.
To find the value of the applied force, we need to first calculate the total mass of the system. Then we can use Newton's second law of motion to calculate the applied force.
1. Calculate the total mass:
The total mass (M) of the system is the sum of the masses of the two blocks: M = m1 + m2.
M = 320 g + 725 g = 1045 g.
2. Convert the total mass to kilograms:
The SI unit of mass is kilograms (kg), so we need to convert the mass from grams to kilograms:
M = 1045 g ÷ 1000 = 1.045 kg.
3. Determine the net force on the system:
Newton's second law of motion states that the net force (F_net) acting on an object is equal to the product of its mass (M) and its acceleration (a): F_net = M * a.
F_net = 1.045 kg * 225 cm/s^2.
Since the unit of force is Newtons (N), we need to convert centimeters to meters:
F_net = 1.045 kg * 2.25 m/s^2.
F_net = 2.34375 N.
Thus, the value of the applied force is approximately 2.34 Newtons.