and for this one I got no clue:
By what percent will the fraction increase if its numerator is decreased by 10% and denominator is decreased by 50%?
can you just show the equation, i can solve it
Let the fraction is x/y so after an increment of 10% numerator will be 11x/10 and after decrement of 50%, the denominator will be y/2 or 5y/10. New fraction will be 11x/5y.
Therefore % of increment = (11x/5y -x/y)*100
= (6x/5y)*100
= 120 (x/y)
Hence fractin will be increase by 120%.
Sure! To find the percentage increase in a fraction when its numerator and denominator are decreased by different percentages, you can follow these steps:
Let the original fraction be represented as (numerator/denominator).
Let the numerator be decreased by x%.
Let the denominator be decreased by y%.
To find the resulting fraction, you can use the following equation:
Resulting fraction = (numerator - (x% of numerator)) / (denominator - (y% of denominator))
In this case, the equation becomes:
Resulting fraction = (numerator - (10% of numerator)) / (denominator - (50% of denominator))
Simplifying further:
Resulting fraction = (numerator - (0.1 * numerator)) / (denominator - (0.5 * denominator))
Now, you can simplify the equation and calculate the value of the resulting fraction. Finally, you can find the percentage increase using the formula:
Percentage Increase = (Resulting fraction - Original fraction) / Original fraction * 100
So, you need to substitute the values of the original numerator and denominator into the equation to calculate the resulting fraction. Finally, plug the values of the original and resulting fractions into the percentage increase formula to find the answer.