algrbra

It is known that a>0 and b<0. Compare the values of the following expressions to zero:

ab^2

i dont understand why i always get these wrong, i pluged in numbers that match with what it says and i solve:
1*-1^2=-1, 0 is greater than ab^2

but i got that wrong i dont understand why though

  1. 0
  2. 0
  3. 5
asked by Ashly
  1. If you are using 1, -1 * -1 = 1

    1 * (-1^2) = 1 * 1 = 1

    1. 0
    2. 0
    posted by PsyDAG
  2. b^2 is always positive, so since a>0,

    ab^2 > 0

    1. 0
    2. 0
    posted by Steve

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