If it is given that P(A)=1/3 and P(B/A)=2/3 (the dividing sign is ment to be a vertical bar), what is P(A and B). I got .07. Is this correct? If it isn't, why not?
Bayes Theorem
P(A,B) = P(B|A)*P(A)=1/3 * 2/3= 2/9=.222
So how did you get .07?
P(A,B) = P(B|A)*P(A)=1/3 * 2/3= 2/9=.222
So how did you get .07?