Here's the question I'm having trouble with:
Tell how you would identify the intercepts for the graph of the equation:
3x + 6y = 18
I'm not exactly sure how you would find the intercepts from this equation.
Thanks!
would you know how to find them if you put it into y=mx+b form?
Yes! I see, I didn't really think of it that way until after I posted the message. Thank you!
lol wow i actually helped ?!
i was just guessing .. im only in grade 11 anyways
If they are written in the form you have, it is often very easy to find
remember to find the x-intercept you let y=0 and to
find the y-intercept you let the x=0
of course letting some variable equal to zero makes that term disappear.
so to let x=0, block out the x term with your little finger, what do you see?
6y = 18, then y = 3
for the x-intercept, block out the y-term with your little finger and ...
x = 6
this works really neat if the x and y coefficients both divide evenly into the constant
To identify the intercepts for the graph of the equation 3x + 6y = 18, you can use a method called "setting x or y as zero."
First, let's find the x-intercept. To find this, we set y equal to zero in the equation and solve for x. So, we substitute 0 for y and solve for x:
3x + 6(0) = 18
3x + 0 = 18
3x = 18
x = 18/3
x = 6
Therefore, the x-intercept is (6, 0), which means the graph crosses the x-axis at the point (6, 0).
Next, let's find the y-intercept. To find this, we set x equal to zero in the equation and solve for y. So, we substitute 0 for x and solve for y:
3(0) + 6y = 18
0 + 6y = 18
6y = 18
y = 18/6
y = 3
Therefore, the y-intercept is (0, 3), which means the graph crosses the y-axis at the point (0, 3).
In summary, the x-intercept is (6, 0) and the y-intercept is (0, 3) for the graph of the equation 3x + 6y = 18.