Calculate the final concentration of ONPG (in μM) if you add 6.16 mL of 3.3 μM ONPG and dilute to a final volume of 10 mL with PBS buffer.

I thought you would use M1V1 = M2V2 however it came up wrong

I know we are adding 3.84 mL of PBS to the 6.16 mL of ONPG to make a final volume of 10 mL, however, I have no clue how to find the final concentration.

Any help is greatly appreciated

To calculate the final concentration of ONPG in μM, you can use the formula:

M1V1 = M2V2

Where:
M1 = initial concentration of ONPG (in μM)
V1 = initial volume of ONPG (in mL)
M2 = final concentration of ONPG (in μM)
V2 = final volume after dilution (in mL)

Using this formula, we can set up the equation:
(3.3 μM)(6.16 mL) = M2(10 mL)

Now, let's solve for M2 (the final concentration):
M2 = (3.3 μM)(6.16 mL) / 10 mL
M2 = 2.0352 μM

Therefore, the final concentration of ONPG in the given solution is approximately 2.0352 μM.