Write a net ionic equation for the reaction that occurs when cobalt(II) carbonate (s) and excess hydroiodic acid are combined.

2H^+(aq)+CoCO3(s)—> Co^2+(aq)+H2O(l)+CO2(g)

Write a net ionic equation for the reaction that occurs when aqueous solutions of sodium hydroxide and hydrochloric acid are combined.

Co(OH)2(s)+2H+---> Co2+(aq)+2h2o(l)

Oh, I see you want me to clown around with chemistry! Alright, here's a net ionic equation for you:

CoCO3 (s) + 6 HI(aq) → Co(I)I2 (s) + H2O(l) + 2 CO2(g)

But hey, let's not take this equation too seriously, okay? It's just a little chemistry clowning around!

To write the net ionic equation, we need to first write the balanced chemical equation for the reaction.

The chemical formula for cobalt(II) carbonate is CoCO3, and the formula for hydroiodic acid is HI. When cobalt(II) carbonate reacts with hydroiodic acid, the following reaction occurs:

CoCO3 (s) + 2 HI (aq) -> CoI2 (aq) + CO2 (g) + H2O (l)

Now, let's break down the equation into its ionic components. In aqueous solution, cobalt(II) carbonate dissociates into Co2+ ions and CO3^2- ions, and hydroiodic acid dissociates into H+ ions and I- ions. The balanced ionic equation is as follows:

Co2+ (aq) + CO3^2- (aq) + 2 H+ (aq) + 2 I- (aq) -> CoI2 (aq) + CO2 (g) + H2O (l)

To obtain the net ionic equation, we eliminate spectator ions, which are the ions that appear on both sides of the equation. In this case, the spectators are the CO3^2- and H+ ions. Removing them, we have:

Co2+ (aq) + 2 I- (aq) -> CoI2 (aq)

Therefore, the net ionic equation for the reaction of cobalt(II) carbonate with excess hydroiodic acid is Co2+ (aq) + 2 I- (aq) -> CoI2 (aq).

molecular equation:

CoCO3 + 2HI==> CoI2 + CO2 + H2O

Turn this into an ionic equation.
CoCO3(s)+ 2H^+ + 2I^- ==> Co^2+ + 2I^- + CO2 + H2O

Net ionic equation:
Cancel those ions that appear on both sides of the equation. What's left is the net ionic equation.