calculate the specific heat capacity of the materials for which the heat supply, mass, and temperature below: (i) 2.52 x 10^4j, 0.3 kg, 20 k (ii) 8 x 10^3j, 500g, from 20'c to 60'c (iii) 9.45 x 10^3j, 150g, from 15'c to 45'c
To calculate the specific heat capacity (c) of a material, we can use the formula:
c = Q / (m * ΔT)
Where:
c = specific heat capacity
Q = heat supplied to the material
m = mass of the material
ΔT = change in temperature
Let's calculate the specific heat capacity for each case:
(i) Q = 2.52 x 10^4 J, m = 0.3 kg, ΔT = 20 K
c = (2.52 x 10^4 J) / (0.3 kg * 20 K)
c ≈ 420 J/(kg·K)
Therefore, the specific heat capacity of the material in case (i) is approximately 420 J/(kg·K).
(ii) Q = 8 x 10^3 J, m = 500 g, ΔT = 60 °C - 20 °C = 40 K
We need to convert the mass to kilograms:
m = 500 g / 1000 = 0.5 kg
c = (8 x 10^3 J) / (0.5 kg * 40 K)
c ≈ 400 J/(kg·K)
Therefore, the specific heat capacity of the material in case (ii) is approximately 400 J/(kg·K).
(iii) Q = 9.45 x 10^3 J, m = 150 g, ΔT = 45 °C - 15 °C = 30 K
We need to convert the mass to kilograms:
m = 150 g / 1000 = 0.15 kg
c = (9.45 x 10^3 J) / (0.15 kg * 30 K)
c ≈ 2100 J/(kg·K)
Therefore, the specific heat capacity of the material in case (iii) is approximately 2100 J/(kg·K).
To calculate the specific heat capacity of a material, we use the formula:
specific heat capacity (c) = heat supplied (Q) / (mass (m) × change in temperature (ΔT))
Now, let's calculate the specific heat capacity for each case:
(i) Heat supply (Q) = 2.52 x 10^4 J
Mass (m) = 0.3 kg
Change in temperature (ΔT) = 20 K
Substituting these values into the formula:
specific heat capacity (c) = (2.52 x 10^4 J) / (0.3 kg × 20 K)
= 420 J/(kg·K)
(ii) Heat supply (Q) = 8 x 10^3 J
Mass (m) = 500 g = 0.5 kg (since 1 kg = 1000 g)
Change in temperature (ΔT) = 60 °C - 20 °C = 40 K
Substituting these values into the formula:
specific heat capacity (c) = (8 x 10^3 J) / (0.5 kg × 40 K)
= 400 J/(kg·K)
(iii) Heat supply (Q) = 9.45 x 10^3 J
Mass (m) = 150 g = 0.15 kg (since 1 kg = 1000 g)
Change in temperature (ΔT) = 45 °C - 15 °C = 30 K
Substituting these values into the formula:
specific heat capacity (c) = (9.45 x 10^3 J) / (0.15 kg × 30 K)
= 2100 J/(kg·K)
Therefore, the specific heat capacities are:
(i) 420 J/(kg·K)
(ii) 400 J/(kg·K)
(iii) 2100 J/(kg·K)