How may particles are there in:
in 1 mole of silicon?
in 2 moles of fluorine?
in 31g phosphorous?
in 18g water?
please help im confused especially with the last one and the second last one second
a mole is a number , like a dozen
dozen = 12 , mole = 6.02E23
6.02E23 ... atoms
2 * 6.02E23 ... atoms
molar mass is 31 g ... so, 6.02E23
... atoms
molar mass is 18 g ... so, 6.02E23
... molecules
I thought the last two were different I got
for 31g phosphorous:
5.149501661 X 10-23
for 18g water:
2.990033223 X 10-23
Scott I dont get what you meant by your last two answers
Please note that P is spelled posphorus
the atomic mass of P is 31
... this means that one mole of P has a mass of 31 g
... P is an element, so the "particles" are atoms
similarly with the water question
... water is a compound, so the "particles" are molecules
I see I can't spell phosphorus either.
To determine the number of particles in a given substance, we need to use Avogadro's constant, which is approximately 6.022 × 10^23 particles per mole.
1. For 1 mole of silicon:
We can directly use Avogadro's constant to determine that there are approximately 6.022 × 10^23 particles in 1 mole of silicon.
2. For 2 moles of fluorine:
We can multiply the number of moles by Avogadro's constant to find the number of particles. Therefore, the number of particles in 2 moles of fluorine is approximately 2 × 6.022 × 10^23 = 1.2044 × 10^24 particles.
3. For 31g of phosphorus:
First, we need to determine the number of moles of phosphorus in 31g using the molar mass of phosphorus. The molar mass of phosphorus is approximately 31g/mol. Therefore, the number of moles in 31g of phosphorus is 31g / 31g/mol = 1 mole. Since 1 mole contains 6.022 × 10^23 particles, there are approximately 6.022 × 10^23 particles in 31g of phosphorus.
4. For 18g of water (H2O):
We need to break down the compound into its individual elements to calculate the number of particles. For water (H2O), we have 2 moles of hydrogen (H) and 1 mole of oxygen (O).
First, calculate the moles of hydrogen in 18g of water:
Using the molar mass of hydrogen (approx. 1g/mol), we find that there are 18g / 1g/mol = 18 moles of hydrogen in 18g of water.
Next, calculate the moles of oxygen in 18g of water:
Using the molar mass of oxygen (approx. 16g/mol), we find that there are 18g / 16g/mol = 1.125 moles of oxygen in 18g of water.
Since we have 2 moles of hydrogen and 1 mole of oxygen in water, we take the lower value of the two (1.125 moles of oxygen) as the limiting reactant. Therefore, there are approximately 1.125 moles × 6.022 × 10^23 particles/mol = 6.77 × 10^23 particles in 18g of water.
To summarize:
- 1 mole of silicon has approximately 6.022 × 10^23 particles.
- 2 moles of fluorine have approximately 1.2044 × 10^24 particles.
- 31g of phosphorus has approximately 6.022 × 10^23 particles.
- 18g of water (H2O) has approximately 6.77 × 10^23 particles.