What mass of NaNO3 can be formed by 0.20 grams of NaSO4.3H20?
To find the mass of NaNO3 formed from Na2SO4∙3H2O, you need to use stoichiometry, which is the relationship between the amounts of reactants and products in a balanced chemical equation.
The balanced chemical equation for the reaction between Na2SO4∙3H20 and an acid could be:
Na2SO4∙3H20 + 2HCl → 2NaCl + H2SO4 + 3H2O
From the balanced equation, you can see that for every 1 mole of Na2SO4∙3H20, 2 moles of NaCl are formed. Therefore, you need to convert the given mass of Na2SO4∙3H20 to moles, and then use the ratio from the balanced equation to calculate the mass of NaNO3 formed.
Here's the step-by-step process:
Step 1: Calculate the molar mass of Na2SO4∙3H20:
- Na2SO4: 2(Na) + 1(S) + 4(O) = 46.0 g/mol
- H2O: 2(H) + 16(O) = 18.0 g/mol
- Total molar mass = 46.0 g/mol + 3(18.0 g/mol) = 166.0 g/mol
Step 2: Convert the given mass of Na2SO4∙3H20 to moles:
- Moles = Mass / Molar mass
- Moles = 0.20 g / 166.0 g/mol ≈ 0.0012 mol
Step 3: Use the stoichiometry ratio to find the moles of NaNO3:
- From the balanced equation, the ratio of Na2SO4∙3H20 to NaNO3 is 1:2
- Moles of NaNO3 = 0.0012 mol Na2SO4∙3H20 × (2 mol NaNO3 / 1 mol Na2SO4∙3H20) = 0.0024 mol NaNO3
Step 4: Convert the moles of NaNO3 to mass:
- Mass = Moles × Molar mass
- Mass = 0.0024 mol × 85.0 g/mol (molar mass of NaNO3) ≈ 0.20 g NaNO3
Therefore, approximately 0.20 grams of NaNO3 can be formed from 0.20 grams of Na2SO4∙3H20.