Algebra 2

Solve the system by substitution
2x-y+z=-4
z=5
-2x+3y-z=-10
I think the answer is (-8,-7,5)
But can someone tel me the right one and explain I’m so lost

asked by Kk
  1. 2x - y + 5 = -4 ... 2x - y = -9

    -2x + 3y - 5 = -10 ... -2x + 3y = -5

    adding equations (to eliminate x)
    ... 2y = -14

    posted by Scott

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