PCl3 (s) + Cl2 (g) -> PCl5 (s)
1. WHAT VOLUME OF Cl2 would react with 1.4g of PCl3 to make PCl5?
2. IF YOU WANTED to make 10g of PCl5, what volume of Cl2 would you need?
3. WHAT IS THE MAXIMUM MASS of PCl5 that could be made from 360cm3 of cl2?
I am very stuck on these and don't know how to do them please help!!!
See your post above. Same kind of stoichiometry problem.
Please help with this question I still need help specific to this question
Sure, I can help you with that!
To solve these stoichiometry problems, we'll need to use the balanced chemical equation and the molar ratios of the reactants and products.
The balanced chemical equation is:
PCl3 (s) + Cl2 (g) -> PCl5 (s).
1. To find the volume of Cl2 that would react with 1.4g of PCl3, we'll follow these steps:
- Convert the mass of PCl3 to moles: divide the given mass by the molar mass of PCl3.
- Use the balanced equation to determine the mole ratio between PCl3 and Cl2. In this case, the ratio is 1:1.
- Use the molar volume of a gas at STP (Standard Temperature and Pressure) to convert the moles of Cl2 to volume. The molar volume at STP is approximately 22.4 L/mol.
2. To determine the volume of Cl2 needed to produce 10g of PCl5, we'll follow these steps:
- Convert the mass of PCl5 to moles: divide the given mass by the molar mass of PCl5.
- Use the balanced equation to determine the mole ratio between PCl5 and Cl2. In this case, the ratio is also 1:1.
- Use the molar volume of a gas at STP to convert the moles of Cl2 to volume.
3. To calculate the maximum mass of PCl5 that could be produced from 360 cm3 of Cl2, we'll follow these steps:
- Convert the volume of Cl2 to moles using the molar volume at STP.
- Use the balanced equation to determine the mole ratio between Cl2 and PCl5. In this case, the ratio is 1:1.
- Convert the moles of PCl5 to grams by multiplying by the molar mass of PCl5.
Let's solve these step by step. First, we'll find the molar masses of the compounds involved.
- Molar mass of PCl3 = 31.00 g/mol (1 phosphorus atom and 3 chlorine atoms)
- Molar mass of Cl2 = 70.90 g/mol (2 chlorine atoms)
- Molar mass of PCl5 = 208.25 g/mol (1 phosphorus atom and 5 chlorine atoms)
Now, let's solve each question.
1. What volume of Cl2 would react with 1.4g of PCl3 to make PCl5?
- Convert the mass of PCl3 to moles: 1.4 g / 31.00 g/mol = 0.045 moles of PCl3
- According to the balanced equation, 1 mole of PCl3 reacts with 1 mole of Cl2.
- Therefore, 0.045 moles of PCl3 would react with 0.045 moles of Cl2.
- Convert moles of Cl2 to volume using the molar volume at STP: 0.045 moles * 22.4 L/mol = 1.008 L (rounded to three decimal places).
2. If you wanted to make 10g of PCl5, what volume of Cl2 would you need?
- Convert the mass of PCl5 to moles: 10 g / 208.25 g/mol = 0.048 moles of PCl5
- According to the balanced equation, 1 mole of PCl5 reacts with 1 mole of Cl2.
- Therefore, 0.048 moles of PCl5 would react with 0.048 moles of Cl2.
- Convert moles of Cl2 to volume using the molar volume at STP: 0.048 moles * 22.4 L/mol = 1.075 L (rounded to three decimal places).
3. What is the maximum mass of PCl5 that could be made from 360 cm3 of Cl2?
- Convert the volume of Cl2 to moles using the molar volume at STP: 360 cm3 * (1 L/1000 cm3) * (1 mol/22.4 L) = 0.016 moles of Cl2
- According to the balanced equation, 1 mole of Cl2 reacts with 1 mole of PCl5.
- Therefore, 0.016 moles of Cl2 would produce 0.016 moles of PCl5.
- Convert moles of PCl5 to grams using the molar mass: 0.016 moles * 208.25 g/mol = 3.332 g (rounded to three decimal places).
I hope this helps you understand how to solve these stoichiometry problems! If you have any further questions, feel free to ask.