If a solution has a total mass of 26.7g and is 8.36 % by weight in sodium chloride, what mass of sodium chloride is present in the solution?

How many moles of dextrose (C6H12O6) are in 414mL of solution with a concentration of 0.84M?

If an aqueous solution is 7.82 % by weight in sodium chloride and contains 1.07 g of sodium chloride, what mass of water is present in the solution?

What mass in grams of dextrose (C6H12O6) will be required to produce 5.00 L of a 0.31M aqueous solution?

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Thank you it helped alot

Sure! Let's solve each question step-by-step:

1. To find the mass of sodium chloride in the solution:
Given:
- Total mass of the solution = 26.7 g
- Sodium chloride concentration = 8.36% by weight

Step 1: Convert the given concentration to a decimal value:
Sodium chloride concentration = 8.36 / 100 = 0.0836

Step 2: Calculate the mass of sodium chloride:
Mass of sodium chloride = Total mass of the solution * Sodium chloride concentration
Mass of sodium chloride = 26.7 g * 0.0836
Mass of sodium chloride = 2.230 g

Therefore, the mass of sodium chloride present in the solution is 2.230 grams.

2. To find the number of moles of dextrose (C6H12O6) in the solution:
Given:
- Volume of the solution = 414 mL
- Concentration of dextrose solution = 0.84 M

Step 1: Convert the volume from milliliters to liters:
Volume of the solution = 414 mL = 414 / 1000 = 0.414 L

Step 2: Use the formula to find the number of moles:
Number of moles of dextrose = Concentration * Volume
Number of moles of dextrose = 0.84 mol/L * 0.414 L
Number of moles of dextrose = 0.34896 mol

Therefore, there are 0.34896 moles of dextrose (C6H12O6) in the solution.

3. To find the mass of water in the solution:
Given:
- Sodium chloride concentration = 7.82% by weight
- Mass of sodium chloride = 1.07 g

Step 1: Convert the given concentration to a decimal value:
Sodium chloride concentration = 7.82 / 100 = 0.0782

Step 2: Calculate the mass of water:
Mass of water = Mass of sodium chloride / Sodium chloride concentration
Mass of water = 1.07 g / 0.0782
Mass of water = 13.693 g

Therefore, the mass of water present in the solution is 13.693 grams.

4. To find the mass of dextrose (C6H12O6) required to produce the given solution:
Given:
- Volume of the solution = 5.00 L
- Concentration of dextrose solution = 0.31 M

Step 1: Use the formula to find the number of moles:
Number of moles of dextrose = Concentration * Volume
Number of moles of dextrose = 0.31 mol/L * 5.00 L
Number of moles of dextrose = 1.55 mol

Step 2: Calculate the molar mass of dextrose (C6H12O6):
Molar mass of dextrose = (6 * atomic mass of carbon) + (12 * atomic mass of hydrogen) + (6 * atomic mass of oxygen)
Molar mass of dextrose = (6 * 12.01) + (12 * 1.01) + (6 * 16.00)
Molar mass of dextrose = 180.18 g/mol

Step 3: Calculate the mass of dextrose:
Mass of dextrose = Number of moles of dextrose * Molar mass of dextrose
Mass of dextrose = 1.55 mol * 180.18 g/mol
Mass of dextrose = 279.279 g

Therefore, the mass of dextrose (C6H12O6) required to produce 5.00 L of a 0.31M aqueous solution is 279.279 grams.

I hope this helps! If you have any more questions, feel free to ask.

To solve these questions, we need to use the concept of percent composition, molar mass, and concentration.

1. Mass of sodium chloride in the solution:
To find the mass of sodium chloride in the solution, we can use the percent composition formula:
Mass of sodium chloride = Total mass of solution * Percent of sodium chloride / 100
Mass of sodium chloride = 26.7 g * 8.36% / 100 = 2.232 g

Therefore, the mass of sodium chloride present in the solution is 2.232 grams.

2. Moles of dextrose in the solution:
To find the moles of dextrose in the solution, we can use the molarity formula:
Moles of solute = Concentration * Volume
However, we need to convert the volume from mL to liters:
Volume = 414 mL * (1 L / 1000 mL) = 0.414 L

Moles of dextrose = 0.84 M * 0.414 L = 0.34896 moles

Therefore, there are approximately 0.349 moles of dextrose (C6H12O6) in 414 mL of the solution.

3. Mass of water in the solution:
To find the mass of water in the solution, we can use the percent composition formula:
Mass of water = Total mass of solution - Mass of sodium chloride
Mass of water = 1.07 g / 7.82% * 100 = 13.686 g

Therefore, the mass of water present in the solution is approximately 13.686 grams.

4. Mass of dextrose required to produce the solution:
To find the mass of dextrose required, we can use the molarity formula:
Moles of solute = Concentration * Volume

First, we need to convert the volume from liters to milliliters:
Volume = 5.00 L * 1000 mL/L = 5000 mL

Moles of dextrose = 0.31 M * 5000 mL / 1000 = 1.55 moles

Finally, we can calculate the mass using the molar mass of dextrose:
Mass of dextrose = Moles of dextrose * Molar mass of dextrose
Mass of dextrose = 1.55 moles * (6 * 12.01 g/mol + 12 * 1.01 g/mol + 6 * 16.00 g/mol) = 316.70 g

Therefore, approximately 316.70 grams of dextrose (C6H12O6) will be required to produce 5.00 L of a 0.31M aqueous solution.

1. %w/w = (g solute)*100/mass solution.

Substitute and solve for g solute.

2. mols = M x L = ?

3. See #1 above and solve for mass solution. Then mass solution = mass solvent + mass solute = ? Substitute and solve for mass solvent.

4. mols = M x L = ?
Then mols = grams/molar mass. You know molar mass and mols, solve for grams.

Post your work if you get stuck.