how do i prepare a 500g/L solution of ethylene glycol
ethylene glycol is about 10% denser than water , so the solution is more than half water (less than half glycol) by volume
a) fill a container halfway with water
b) measure the appropriate amount of glycol
... based on container size/solution amount
... add to water and mix well
c) add water to appropriate solution volume
you can measure the glycol by taring a beaker and then adding the glycol with the beaker on a scale
remember to rinse ALL of the glycol into the solution
To prepare a 500g/L (grams per liter) solution of ethylene glycol, you will need to know the density and purity of your ethylene glycol. The density will help you determine the volume of ethylene glycol required to reach the desired concentration.
Here's a step-by-step guide:
1. Determine the purity of your ethylene glycol. For example, if it is 99% pure, it means that 99g of the 100g is ethylene glycol, and the remaining 1g is impurities.
2. Determine the density of your ethylene glycol. The density is usually provided on the label or in the product specifications. Let's say the density is 1.113g/mL.
3. Calculate the volume of ethylene glycol needed by dividing the desired mass (500g) by the density:
Volume (in mL) = Mass (in g) / Density (in g/mL)
Volume (in mL) = 500g / 1.113g/mL
Volume (in mL) ≈ 449 mL (rounded to three decimal places)
4. Convert the volume to liters by dividing by 1000 (since there are 1000 mL in a liter):
Volume (in L) = Volume (in mL) / 1000
Volume (in L) = 449 mL / 1000
Volume (in L) ≈ 0.449 L (rounded to three decimal places)
5. Now, use a measuring cylinder or graduated container to measure 0.449 liters of ethylene glycol.
6. Transfer the measured ethylene glycol into a container or flask.
7. Add distilled water to the container, while stirring, until the total volume reaches 1 liter.
8. Stir the mixture thoroughly to ensure proper mixing.
Following these steps should help you prepare a 500g/L solution of ethylene glycol with the given purity and density information.