anderly chooses three different whole numbers. The largest number is 3 times the smallest number. The middle number is 3 less than the largest number. The sum of the number is three numbers is greater than 30 and smaller than 35. Write an expression for the sum of the three numbers
The numbers are x,y,z. The 3rd condition is a bit murky, but it appears that we have
z = 3x
y = z-3
30 < x+y+z < 35
30 < x + (3x-3) + 3x < 35
30 < 7x-3 < 35
33 < 7x < 38
4.7 < x < 5.4
so, x=5
The numbers are 5,12,15 with sum=32
To solve this problem, we'll need to set up some equations to represent the given information.
Let's assume the smallest number is x.
According to the given information, the largest number is 3 times the smallest number, so the largest number would be 3x.
The middle number is stated to be 3 less than the largest number. Therefore, the middle number would be 3x - 3.
Now, we can write an expression for the sum of the three numbers:
Sum = x + (3x - 3) + 3x
Simplifying the expression:
Sum = x + 3x - 3 + 3x
= 7x - 3
So, the sum of the three numbers is represented by the expression 7x - 3.