Twice the smallest of three consecutive odd integers is eleven more than the largest. Find the integers. Please help I don't understand these type of math question
Smallest = X.
Middle = x+1.
Largest = x+2.
2x = (x+2) + 11.
X = 13.
x+1 = 13+1 = 14.
x+2 = 13+2 = 15.
To solve this problem, let's assume the smallest odd integer is represented by the variable "x".
According to the given information, the three consecutive odd integers are x, x+2, and x+4.
We are given that twice the smallest of the three consecutive odd integers is eleven more than the largest. Mathematically, this can be represented as:
2x = (x+4) + 11
Now, let's solve this equation to find the value of x:
2x = x + 15 (Combine like terms)
2x - x = 15 (Subtract x from both sides)
x = 15
Therefore, the smallest odd integer is 15.
To find the other two consecutive odd integers, we can substitute the value of x back into the equation:
x+2 = 15 + 2 = 17
x+4 = 15 + 4 = 19
So, the three consecutive odd integers are 15, 17, and 19.
Sure! I'll be happy to explain how to approach this math question.
First, let's understand the problem. We are looking for three consecutive odd integers. Let's represent the smallest odd integer as "x". Since they are consecutive, the next odd integer would be "x + 2" (because the difference between consecutive odd integers is always 2), and the largest odd integer would be "x + 4" (since there is another odd integer between x and x + 2).
Now, according to the problem, twice the smallest integer is equal to eleven more than the largest integer. We can write this as an equation:
2x = (x + 4) + 11
Let's solve this equation step by step:
2x = x + 15 (Combined like terms on the right side)
2x - x = 15 (Subtracted "x" from both sides)
x = 15 (Simplified)
So, we have found that the smallest odd integer, represented by "x," is 15.
Now we can find the other two odd integers:
The next odd integer = x + 2 = 15 + 2 = 17
The largest odd integer = x + 4 = 15 + 4 = 19
Therefore, the three consecutive odd integers are 15, 17, and 19.
I hope this helps! If you have any more questions, feel free to ask.