A spinner turns 7077 degrees. The spinner would have ended up at the same spot if it had turned only what degree?
A) 77
B) 2197
C) 4377
D) 4917
E) 5537
4917
7077 = 360*19 + 237
...
To find out the degree at which the spinner would have ended up if it had turned only a certain degree, we need to determine the remainder when 7077 is divided by the total number of degrees in one complete revolution, which is 360 degrees.
Dividing 7077 by 360 gives us a quotient of 19 and a remainder of 237.
Therefore, the spinner would have ended up at the same spot if it had turned only 237 degrees.
Among the given options, the closest degree to 237 is 2197.
So the correct answer is:
B) 2197
To solve this problem, we need to find the remainder when 7077 is divided by 360 (the number of degrees in one full rotation of the spinner).
We can calculate the remainder by using the modulus operator (%).
7077 % 360 = 297
The remainder is 297 degrees.
Therefore, the spinner would have ended up at the same spot if it had turned only 297 degrees more or less than 7077 degrees.
To find the equivalent degree that would bring the spinner back to the same spot, we can subtract or add 297 degrees to 7077 degrees.
7077 - 297 = 6780
7077 + 297 = 7374
So, the spinner would end up at the same spot if it had turned either 6780 degrees or 7374 degrees.
Among the given options, the degree 7374 is not listed.
Therefore, the correct answer is not listed among the given options.