Hello!
Thanks for checking my question out!
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5. If the volume of a cylinder is reduced from 8.0 liters to 4.0 liters, the pressure of the gas in the cylinder will change from 70 kilopascals to (1 point)
a) 35 kilopascals.
b) 105 kilopascals.
c) 140 kilopascals.
d) 560 kilopascals.
My Answer: C
Could someone please check my answer?
Thanks!
- Da Fash
yes.P1*V1 = P2*V2
To find the answer, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when the temperature is constant. In other words, as the volume decreases, the pressure will increase, and vice versa.
Let's calculate the pressure change:
Initial volume (V1) = 8.0 liters
Final volume (V2) = 4.0 liters
Initial pressure (P1) = 70 kilopascals
According to Boyle's Law:
P1 * V1 = P2 * V2
Plugging in the values we have:
70 kilopascals * 8.0 liters = P2 * 4.0 liters
Simplifying this equation:
560 kilopascals = P2 * 4.0 liters
To find P2, we need to isolate it:
P2 = 560 kilopascals / 4.0 liters
P2 = 140 kilopascals
From our calculations, we find that the final pressure (P2) will be 140 kilopascals. Therefore, the correct answer is option c) 140 kilopascals.
So, your answer is correct! Well done!