percy borrowed $1000 at 9% per annum simple interest.she is to repay the debt with 3 equal payments;the 1st at the end of 3 months,the 2nd at the end of 6 months and the 3rd at the end of 9 months.determine the size of the payments using the focal date at the preseent time

Since she is borrowing for 9 months, her total interest is 9/12 x 9%=6.75%. 1.0675 x 1000=1067.5 total payments.

1067.5/3=$355.83 due at the end of 3, 6, and 9 months.
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To determine the size of the payments, we can use the formula for calculating simple interest:

Interest = Principal * Rate * Time

In this case, the principal (P) is $1000, and the rate (R) is 9% per annum, or 0.09. However, we need to calculate the interest for each payment separately.

1. First payment (at the end of 3 months):
The time (T) for the first payment is 3 months, which is 3/12 = 0.25 years.
Interest = 1000 * 0.09 * 0.25 = $22.50

2. Second payment (at the end of 6 months):
The time (T) for the second payment is 6 months, which is 6/12 = 0.5 years.
Interest = 1000 * 0.09 * 0.5 = $45.00

3. Third payment (at the end of 9 months):
The time (T) for the third payment is 9 months, which is 9/12 = 0.75 years.
Interest = 1000 * 0.09 * 0.75 = $67.50

Now, let's calculate the total interest:

Total Interest = Interest first payment + Interest second payment + Interest third payment
= $22.50 + $45.00 + $67.50
= $135.00

Since the total debt is $1000, the total amount to be repaid will be the principal plus the interest:

Total Amount = Principal + Total Interest
= $1000 + $135.00
= $1135.00

Since the payments are to be made in 3 equal installments, each payment will be:

Size of Payment = Total Amount / Number of Installments
= $1135.00 / 3
= $378.33

Therefore, the size of each payment will be approximately $378.33.