I am confused on how to find out if a rhombus diagonals are perpendicular?
A (0, 2) B (3, 6) C (5, 1) D (2,-3).
m of AC =-1/5
m of BD = -9/1
Now I am stuck I don't know how to figure if it is perpendicular or not? Help?
your slope for BD should have been 9/1 or 9
To be a rhombus, the slopes of the diagonals should have been negative reciprocals of each other
the negative reciprocal of -1/5 would be +5
which it isn't.
so ABCD is not a rhombus
Another way to check: The sides are not equal
that is,
AB = √(3^2 + 4^2) = 5
BC = √(2^2 + 5^2) = √29