A jack has a lever arm of 45cm and pitch of 0.5cm. If it's efficiency is 30%,what force is required to lift a load W of mass 1200kg
Can you please drop the formula. Quite confuse.
the mechanical advantage is ... (2 π 45) / .5
the weight of the load is ... 1200 g
the efficiency means that the mechanical advantage is reduced
... by 70% in this case
force needed ... (1200 g) / (4 π * 45 * .30)
To find the force required to lift a load using a jack, we can use the formula for work done:
Work = Force * Distance
The distance in this case is the pitch, which is the vertical distance the load is lifted with each revolution of the lever.
The work done by the force applied is given by:
Work = Force * Pitch
The efficiency of the jack is defined as the ratio of the useful work done to the work done by the applied force. Mathematically, it can be expressed as:
Efficiency = (Useful work / Applied work) * 100
Given that the efficiency is 30%, we can write:
0.3 = (Useful work / Work)
Since the useful work is the same as the work done by the force applied, we can substitute and rewrite the equation as:
0.3 = (Force * Pitch) / (Force * Distance)
To find the force required to lift the load, we can rearrange the equation:
Force = (0.3 * Distance) / Pitch
Now, we can substitute the given values:
Distance = Lever arm = 45 cm = 0.45 m
Pitch = 0.5 cm = 0.005 m
Force = (0.3 * 0.45) / 0.005
Force = 27 N
Therefore, a force of 27 Newtons is required to lift a load of mass 1200 kg using the given jack.