How many ODD three digit numbers is it possible to make using the numbers 4, 5 and 7 if you are allowed to use each of the numbers more than once in a particular three digit number?
thanks so much my guy ur the best
You have 3 choices for the first digit
and 3 choices for the middle digit, but
only 2 choices for the last digit
number of possible numbers = (3)(3)(2) = 18
Well, let's see. If we're only using the numbers 4, 5, and 7, we can create six three-digit numbers: 455, 457, 475, 477, 545, and 547. Out of these six numbers, we can only form two odd three-digit numbers: 455 and 547. So, the answer is two. It looks like those numbers are feeling pretty "odd" today!
To determine the number of odd three-digit numbers using the numbers 4, 5, and 7, we need to consider the possible combinations.
Step 1: Determine the choices for the hundreds place:
Since we can use each number more than once, any of the three numbers (4, 5, and 7) can be placed in the hundreds place. So there are 3 choices for the hundreds place.
Step 2: Determine the choices for the tens place:
For an odd number, the units place must be an odd digit, which means it must be either 5 or 7. So there are 2 choices for the units place.
Since we can use each number more than once, any of the three numbers (4, 5, and 7) can be placed in the tens place. So there are 3 choices for the tens place.
Step 3: Determine the choices for the units place:
For an odd number, the units place must be an odd digit, which means it must be either 5 or 7. So there are 2 choices for the units place.
Step 4: Calculate the total number of possibilities:
Using the multiplication rule, multiply the number of choices at each step:
Total possibilities = (number of choices for hundreds place) x (number of choices for tens place) x (number of choices for units place)
Total possibilities = 3 x 3 x 2 = 18
Therefore, it is possible to make 18 odd three-digit numbers using the numbers 4, 5, and 7, if you are allowed to use each number more than once.
To find the number of odd three-digit numbers that can be formed using the numbers 4, 5, and 7, we need to determine the possible combinations.
Step 1: Determine the possible options for the hundreds digit.
Since the number needs to be odd, the hundreds digit can only be 4 or 7. So, we have two options for the hundreds digit.
Step 2: Determine the possible options for the tens and units digits.
Since we can use each number more than once, we have all three numbers - 4, 5, and 7 - available to use for both the tens and units digits.
Step 3: Calculate the total number of combinations.
To calculate the total number of combinations, multiply the number of options for each digit. In this case, we have 2 options for the hundreds digit and 3 options for both the tens and units digits.
Total number of combinations = 2 x 3 x 3 = 18
Therefore, it is possible to make 18 odd three-digit numbers using the numbers 4, 5, and 7 if we are allowed to use each of the numbers more than once in a particular three-digit number.