4) The line with slope 6/5 , going through (0, 2). Write equation in Slope Intercept Form.
I am new to this so can you show me a step by step method of solving this problem so i can use it as a practice template.
(1,-5) m=6/5 how I graph
Graph the line passing through (1,-5) whose slope is m=6/5.
a class has 9 girls and 12 boys. what is the probability of a teacher randomly calling on a boy?
There are 9 + 12 = 21 students in total.
The probability of calling on any one boy is the number of boys divided by the total number of students:
P(boy) = 12/21
Simplifying the fraction, we have:
P(boy) = 4/7
Therefore, the probability of a teacher randomly calling on a boy is 4/7 or about 0.57 (rounded to two decimal places).
Sure! To write the equation of a line in slope-intercept form (y = mx + b), you need two pieces of information: the slope (m) and a point on the line (x, y).
Step 1: Identify the given information.
In this case, the slope is 6/5, and the point on the line is (0, 2).
Step 2: Plug the given slope and the coordinates into the slope-intercept form (y = mx + b).
The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept (the y-coordinate where the line crosses the y-axis).
Step 3: Substitute the values.
Replace m with 6/5:
y = (6/5)x + b
Since the line passes through the point (0, 2), we can substitute x with 0 and y with 2:
2 = (6/5)(0) + b
Step 4: Solve for b.
Now we need to find the value of b to complete the equation. Determine what value of b satisfies the equation.
2 = 0 + b
b = 2
Step 5: Substitute the value of b back into the equation.
Now that we know b is 2, we can substitute it back into the original equation:
y = (6/5)x + 2
Therefore, the equation of the line with a slope of 6/5 and going through the point (0, 2) in slope-intercept form is y = (6/5)x + 2.
y = m x + b ... m is slope, b is y-intercept
plug in point ... 2 = 6/5 (0) + b ... 2 = b
y = 6/5 x + 2
y = m x + b ... m is slope, b is y-intercept
plug in point ... 2 = 6/5 (0) + b ... 2 = b
y = 6/5 x + 2