What is the mass of the organic substance formed by heating of 21.0g of butanoate of ammonium, admitting that the reaction presents a yield of 50%?
CH3CH2CH2COONH4 + heat ==>CH3CH2CH2COOH + NH3
21.0 x (mm product acid/mm reactant) x 0.5 = ?
whee mm stands for molar mass.
thanks
To find the mass of the organic substance formed, we need to first calculate the moles of butanoate of ammonium (NH4CH3CH2COO).
Step 1: Calculate the moles of butanoate of ammonium:
Using the molar mass of butanoate of ammonium, which is the sum of the molar masses of its individual elements, we can calculate the number of moles.
Molar mass of NH4CH3CH2COO = (4 * atomic mass of hydrogen) + (1 * atomic mass of nitrogen) + (3 * atomic mass of carbon) + (7 * atomic mass of hydrogen) + (2 * atomic mass of oxygen)
Molar mass of NH4CH3CH2COO = (4 * 1.007) + (1 * 14.01) + (3 * 12.01) + (7 * 1.007) + (2 * 16.00)
Molar mass of NH4CH3CH2COO ≈ 117.16 g/mol
Given mass of butanoate of ammonium = 21.0 g
Moles of butanoate of ammonium = mass / molar mass
Moles of butanoate of ammonium = 21.0 g / 117.16 g/mol
Moles of butanoate of ammonium ≈ 0.179 moles
Step 2: Calculate the yield of the reaction:
The yield represents the efficiency of a reaction, expressed as a percentage. In this case, the yield is given as 50%. To calculate the actual mass formed, we need to account for this yield.
Actual mass formed = yield * theoretical mass formed
Actual mass formed = 0.5 * theoretical mass formed
Step 3: Calculate the theoretical mass formed:
Theoretical mass is the mass that would be formed assuming a 100% yield. To calculate the theoretical mass of the organic substance formed, we need to know the balanced chemical equation for the reaction.
Given that the reaction is not specified, we can't determine the exact balanced equation and hence the theoretical mass.
If you have the balanced equation, you can calculate the stoichiometry of the reaction to find the molar ratios and compute the theoretical mass formed.
To summarize, without the balanced equation, we cannot determine the theoretical mass formed. However, we have determined the moles of butanoate of ammonium, and by assuming a 50% yield, we can calculate the actual mass formed once the balanced equation is provided.