point a (-10,-6)and b (6,2) are the endpoints of ab
So? Do you have a question?
can you help me solve i think i left of a part, of ab ..... such that ac 3/4 the length of ab
What do you want to solve?
point a (-10,-6) and b (6,2) are the endpoints of ab.what are the coordinates of point c on ab (1 point)
such that ac is 3/4 the length of ab?
To find the equation of the line passing through points A(-10, -6) and B(6, 2), you can use the slope-intercept form of a linear equation. The slope-intercept form is given by:
y = mx + b
To find the slope (m) of the line, you can use the formula:
m = (y2 - y1) / (x2 - x1)
Using the coordinates of points A and B:
x1 = -10, y1 = -6
x2 = 6, y2 = 2
Substituting these values into the formula, we have:
m = (2 - (-6)) / (6 - (-10))
m = 8 / 16
m = 1/2
Now that we have the slope, we can substitute one of the points (let's use point A) and the slope into the slope-intercept form equation:
y = mx + b
-6 = (1/2)(-10) + b
Simplifying the equation:
-6 = -5/2 + b
-6 + 5/2 = b
-12/2 + 5/2 = b
-7/2 = b
So the equation of the line passing through points A (-10, -6) and B (6, 2) is:
y = (1/2)x - (7/2)