If the buoyancy exerted by water on the stone is 2N.What is the weight of the stone on dipping it in saline water?

The bouyancy will be slightly higher, since the density of saline water is greater than "water". If bouyance is higher, the apparent weight of the stone is less.

To find the weight of the stone on dipping it in saline water, we need to take into account two factors: buoyancy and the density of the liquid.

Buoyancy is the force exerted by a fluid (in this case, water) on a submerged object. It always acts in the opposite direction to the force of gravity. The magnitude of the buoyant force is equal to the weight of the fluid displaced by the object.

Given that the buoyancy exerted by water on the stone is 2N, we know that when the stone is submerged in water, it experiences a buoyant force of 2N in the upward direction.

Now, when we submerge the stone in saline water, which has a higher density than pure water, the buoyant force will be greater since the stone will displace more saline water than pure water due to the higher density. To find the weight of the stone on dipping it in saline water, follow these steps:

Step 1: Determine the density of saline water.
Find the density of saline water by referring to a reliable source or conducting an experiment. The density of water with salt dissolved in it is higher than that of pure water.

Step 2: Calculate the buoyant force in saline water.
Using the density of saline water, calculate the buoyant force using the following formula:
Buoyant force = density of saline water * volume of stone * gravitational acceleration

Step 3: Find the weight of the stone.
The weight of the stone on dipping it in saline water is the difference between the buoyant force exerted by the saline water and the gravitational force acting on the stone:
Weight of the stone = Buoyant force in saline water - Buoyancy exerted by water

By following these steps, you can find the weight of the stone on dipping it in saline water.