A ball of mass 1 kg dropped from 9.8m height , strikes the ground and rebounds to a height of 4.9m .If the time of contact between ball and ground is 0.1s,then find impulse and average force acting on ball.
Answer is wrong..the correct answer is 23.89Ns, 238.9N
The answer given by kundan is almost correct.
But only at the last part where he solve:
9.8*(1+root2)= 9.8*(1+1.414)= 9.8*2.414=23.857
This is where he went wrong
Similarly we can fine force
Answer is wrong
It's a wrong answer
Correct answer is 23.52Ns,235.2N
Answer is wrong..
Thanks for correcting the mistake
Why has -ve sign being used in front of initial velocity ??
Still if uh multiply 9.8*2.414
It comes out to 23.657 and not 23.857
But the answer given here in my material is 23.857
......Question asked by Kundan......
Some favourite answers :
(1) 13.85 by Jitin Sharma
~ Wrong
(2) Correction of Jitin by Sireesha
He forgot to do the sum of √2 + 1
~ Okay
~ But How the (9.8 × 2.414) = 23.857
~ Wrong
(3) Chitransh
Last step -----> [9.8 × 2.414] = 23.657 N-s