Sarah flipped a pair of coins 60 times on 24 occasions, heads appeared on both coins. How is this outcome different from the expected outcome?
It occurred 9 more times than expected
it occurred 4 more times than expected
It occurred 6 fewer times than expected
It occurred the expected number of times
I'm confused on this question, and I need an explanation. Please
coin 1 head tail
==================
coin 2 head tail
so 4 outcomes equally possible
head/head
head/ tail
tail/ head
tail/tail
head/head is 1/4 = p
60/4 = 15 times expected
24 - 15 = 9
Okay, I get it. Thank you.
You are welcome.
To answer this question, we need to understand the expected outcome when flipping a pair of coins. When flipping a fair pair of coins, each individual coin has a 50% chance of landing on heads and a 50% chance of landing on tails. Since these are independent events, the probability of both coins landing on heads is obtained by multiplying their individual probabilities. Therefore, the probability of both coins landing on heads is 0.5 * 0.5 = 0.25 or 25%.
Now, Sarah flipped the pair of coins a total of 60 times and observed heads on both coins on 24 occasions. To determine whether this outcome is different from the expected outcome, we can compare it to the expected number of times both coins would land on heads in 60 flips.
The expected number of times can be calculated by multiplying the total number of flips (60) by the probability of getting heads on both coins (0.25 or 25%). Therefore, the expected number of times both coins would land on heads is 60 * 0.25 = 15.
Now we can compare the observed outcome (24 times) with the expected outcome (15 times):
24 - 15 = 9
The observed outcome of 24 occurrences is 9 more times than the expected outcome of 15 occurrences. So, the correct answer to your question is: "It occurred 9 more times than expected."