A sample of seawater contains 0.000245 g of sodium chlorate per mL of solution How much sodium chloride is contained in 50.0 mL of this solution
watch the units
g/mL * mL = g
To find out how much sodium chloride is contained in the solution, we need to use the given information about the sodium chlorate content and the volume of the solution.
Given:
- Sodium chlorate concentration: 0.000245 g/mL
- Volume of the solution: 50.0 mL
To calculate the amount of sodium chloride, we need to convert the concentration of sodium chlorate to the concentration of sodium chloride. Sodium chlorate (NaClO3) and sodium chloride (NaCl) have different atomic weights, so we can't directly convert the two compounds. We'll need to use a stoichiometric ratio.
The stoichiometric ratio between sodium chlorate and sodium chloride is 1:1. This means that for every 1 mole of sodium chlorate, there is 1 mole of sodium chloride.
To convert the concentration of sodium chlorate to sodium chloride, we need to know the molar mass of sodium chlorate (106.45 g/mol) and sodium chloride (58.44 g/mol).
Using these values, we can calculate the conversion factor:
Conversion factor = Molar mass of NaCl / Molar mass of NaClO3
= 58.44 g/mol / 106.45 g/mol
≈ 0.549
Now, we can calculate the amount of sodium chloride in the solution:
Amount of sodium chloride = Concentration of sodium chlorate x Volume of solution x Conversion factor
= 0.000245 g/mL x 50.0 mL x 0.549
≈ 0.00673 g
Therefore, there are approximately 0.00673 g of sodium chloride in 50.0 mL of the solution.