What will be the molarity of the resultant solution obtained by mixing equal volumes of 1M and 5M ofNaOH.
say you have one liter of each.
That is 1 mol + 5 mols = 6 mols of NaOH
in 2 liters of liquid
so we end up with 3 mols per liter
which is
3M
To find the molarity of the resultant solution obtained by mixing equal volumes of 1M and 5M NaOH, you can use the concept of solution dilution.
Molarity (M) is defined as the moles of solute divided by the volume of the solution in liters.
In the given problem, we are mixing equal volumes of 1M and 5M NaOH solutions. Let's assume that each solution has a volume of V liters.
The number of moles of NaOH in the 1M solution can be calculated by multiplying its molarity (1M) by the volume (V) as follows:
Moles of NaOH in 1M solution = 1M x V = V moles
Similarly, the number of moles of NaOH in the 5M solution can be calculated as:
Moles of NaOH in 5M solution = 5M x V = 5V moles
When we mix these two solutions, the total moles of NaOH will be the sum of the moles of NaOH from both solutions:
Total moles of NaOH = V moles (from 1M solution) + 5V moles (from 5M solution)
= 6V moles
The total volume of the resulting solution will be the sum of the volumes of the two equal volumes of solutions:
Total volume of the resulting solution = V + V = 2V liters
The molarity (M) value of the resulting solution can be calculated by dividing the total moles of solute by the total volume of the solution:
Molarity of the resulting solution = Total moles of NaOH / Total volume of the solution
= 6V moles / 2V liters
= 3M (as moles and liters cancel out)
Therefore, the molarity of the resultant solution obtained by mixing equal volumes of 1M and 5M NaOH solutions is 3M.