Heat of fusion of ice lab

Initial mass of empty cup calorimeter 9.55g
Initial mass of water 200.15g
Initial mass of ice + water 209.7g
Initial temp of water 41.9°C
Initial mass of ice 26.9g
Final mass of cup 9.55g
Final mass of water 227.05g
Final mass of cup + water 236.6g
Final temp of water 26.9°C

Calculate the heat of fusion of ice

the sum of heats gained is zero. You will need the specific heat of the calorimeter.

Heats gained:
calorimeter=9.55*Ccal*(26.9-41.9)
water= 200.15*cwater(26.9-41.9)
icemelting=Hfice*9.7
this assumes the inital temp of ice was 0C
meltedicewater=9.7*Cwater*(26.9-0)

add all those (some are negative, some are positive), set equal to zero, then solve for Hfice

To calculate the heat of fusion of ice, you can use the formula:

Q = m * Hf

where:
Q is the heat transferred,
m is the mass of the ice that melted,
Hf is the heat of fusion of ice.

First, let's calculate the mass of ice that melted:

Mass of ice melted = Initial mass of ice - Final mass of ice
Mass of ice melted = 26.9g - 0g (since no ice remains in the final state)
Mass of ice melted = 26.9g

Next, let's calculate the heat transferred using the formula:

Q = m * Hf

Since we have the mass of ice melted (m) as 26.9g, we need to solve for Hf.

To calculate Q, we can use the equation:

Q = mcΔT

where:
m is the mass of the water,
c is the specific heat capacity of water,
ΔT is the change in temperature.

We can use the initial and final masses of the water to find the mass of water:

Mass of water = Final mass of water - Initial mass of water
Mass of water = 227.05g - 200.15g
Mass of water = 26.9g

Now, let's calculate ΔT (change in temperature):

ΔT = Final temperature - Initial temperature
ΔT = 26.9°C - 41.9°C
ΔT = -15°C

Since we have ΔT and the mass of water, we can calculate Q:

Q = mcΔT
Q = (26.9g)(4.18 J/g°C)(-15°C)
Q = -1728.93 J (rounding to three significant figures)

Now, we can solve for Hf in the equation Q = m * Hf:

-1728.93 J = (26.9g) * Hf

Dividing both sides by 26.9g:

Hf = -1728.93 J / 26.9g
Hf = -64.37 J/g

Therefore, the heat of fusion of ice is approximately -64.37 J/g. The negative sign indicates that heat is being released during the process of the ice melting.