What is the volume of a cube whose surface area is 54?

To find the volume of a cube, we need to know the length of one side. Since we only have the surface area, we need to first find the length of one side. The formula to find the surface area of a cube is: Surface Area = 6 * Side^2.

Let's solve for the side length using the given surface area of 54:

54 = 6 * Side^2

Divide both sides by 6:

9 = Side^2

Take the square root of both sides to solve for the side length:

√9 = √(Side^2)
3 = Side

Now that we know the side length is 3 units, we can calculate the volume of the cube. The formula for determining the volume of a cube is: Volume = Side^3.

Using the side length of 3:

Volume = 3^3
Volume = 27 cubic units

Therefore, the volume of the cube with a surface area of 54 units is 27 cubic units.

To find the volume of a cube when given its surface area, we need to follow a few steps.

Step 1: Recall that the surface area of a cube is given by the formula SA = 6s^2, where "SA" represents the surface area and "s" represents the length of one side of the cube.

Step 2: We know that the surface area of the cube is equal to 54. So we can set up the equation 6s^2 = 54.

Step 3: Divide both sides of the equation by 6 to isolate s^2. This gives us s^2 = 9.

Step 4: Take the square root of both sides to solve for s. The positive square root of 9 is 3, so we find that s = 3.

Step 5: Now that we know the length of one side of the cube is 3, we can find the volume using the formula V = s^3, where "V" represents the volume and "s" is the length of one side.

Step 6: Substitute the value of s into the formula: V = 3^3 = 27.

Therefore, the volume of the cube with a surface area of 54 is 27.

GGGG

the area of a cube of side s is 6s^2. So,

6s^2 = 54
s^2 = 9
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