what is the differential equation of (2xy+1) + (x^2 + 3y^2)dy/dx=0
To determine the differential equation of the given expression, we need to rearrange the equation in terms of dy/dx.
The given equation is:
(2xy + 1) + (x^2 + 3y^2) * dy/dx = 0
To isolate the dy/dx term, we can move the (2xy + 1) term to the other side of the equation:
(x^2 + 3y^2) * dy/dx = - (2xy + 1)
Next, we divide both sides of the equation by (x^2 + 3y^2):
dy/dx = - (2xy + 1) / (x^2 + 3y^2)
Therefore, the differential equation of the given expression is:
dy/dx = - (2xy + 1) / (x^2 + 3y^2)