A blue ball is thrown upward with an initial speed of 20.8 m/s, from a height of 0.6 meters above the ground. 2.5 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 10.4 m/s from a height of 24.6 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2.
ball one:
v = 20.8 - 9.81 t
h = .6 + 20.8 t -4.9 t^2
ball 2
v = -10.4 -9.81(t-2.5)
h = 24.6 - 10.4 (t-2.5) - 4.9(t-2.5)^2
Now you did not say what the question is