2 cylinders are proportional
the smaller cylinder has a radius of 4 centimeters, which is half as large as the radius of the larger cylinder. the volume of smaller cylinder =250 cubic cemtimeters.
what is the volume of the larger cylinder?
radsmall/radiuslarge=heightsmall/heightlarge
volumesmall=250=PI*4^2(heighsmall)
volumelarge=?=PIradiuslarge^2*heightlarge
height small=250/16PI
Height large=?/64PI (radius large=8)
so put these into the proportion...
4/8=(250/16PI)/(?/64PI)
or
1/2=250*4/?
solve for?
bobpursley,cna you dumb iot down for me. thanks
bobpursley, i misspelled some words from my last response, i meant to say can you explain it a little better? because i still don't quiet get it.
thank you
pl=3 &if i solve this problem in a proportion (which is what we've been working on in math) then what would be the point of trying to do the equation
v= pie*r^2*h?
im very confused
please help me with this problem
To find the volume of the larger cylinder, we can use the information given and set up ratios.
Let's assume the radius of the larger cylinder is R cm.
According to the information, the radius of the smaller cylinder is half the size, so it would be R/2 cm.
The volume of a cylinder can be calculated using the formula:
Volume = π * (radius)^2 * height
Since both cylinders have the same height, we don't need to consider it.
So, the ratio of volumes between the smaller and larger cylinders can be expressed as:
(π * (R/2)^2) / (π * R^2) = 250 / V
(π * (R^2/4) ) / (π * R^2) = 250 / V (Simplifying the ratio by canceling out π)
Now, we can cross-multiply to solve for V (volume of the larger cylinder):
R^2 / 4 = 250 / V
Multiply both sides by 4:
R^2 = (250 * 4) / V
R^2 = 1000 / V
Finally, multiply both sides by V and divide by 1000 to isolate R^2:
R^2 * V = 1000
R^2 = 1000 / V
To determine the volume of the larger cylinder, we need to know the value of V (volume of the smaller cylinder). However, you haven't provided that information. If you can provide the volume of the smaller cylinder, I can help you find the volume of the larger cylinder using the equation above.