Chemistry

h2so4 is labelled as 9.8 by weight. specific gravity of h2so4 is 1.8. the volume of acid to be taken to prepare 100 ml of 0.18M solution is?

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  1. Is that 9.8% w/w? I assume so. Then the molarity of the H2SO4 is
    1000 mL x 1.8 g/mL x (9.8/100) x 1/98 = ? which I will label as y.
    Then mL1 x M1 = mL2 x M2
    ....100 mL x 0.18 = mL2 x y
    Solve for mL2

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  2. 10 ml

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  3. M=10×d×y÷gram molecular weight
    M=10(1.8)9.8 ÷ 98
    M=1.8
    M1×V2=M2×V1
    (1.8)V2=1000(0.18)
    V2=100ml

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  4. 9ydljfxjgfutshvkcuorty%7/'rufcugfutx,ufi6dyrc.mbhjj

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  5. Dirty

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