The first day of a water polo tournament the total value of tickets sold was $680. One-day passes sold for
$5 and tournament passes sold for
$10. The number of tournament passes sold was 32 more than the number of day passes sold. How many day passes and tournament passes were sold?- Need a little hint. Help?
5 d + 10 t = 680
and
t = 32 + d
so
5 d + 10(32+d) = 680
Sure! Let's break down the problem step by step.
Step 1: Assign variables
Let's use the variable "x" to represent the number of one-day passes sold. Since the number of tournament passes sold was 32 more than the number of day passes sold, we can express the number of tournament passes sold as "x + 32".
Step 2: Calculate the revenues
The revenue from one-day passes is $5 multiplied by the number of day passes sold, which is 5x. The revenue from tournament passes is $10 multiplied by the number of tournament passes sold, which is 10(x + 32).
Step 3: Set up the equation
Since the total value of tickets sold was $680, we can set up the equation:
5x + 10(x + 32) = 680
You can now solve this equation to find the values of x and x+32.
To solve this problem, let's use variables to represent the number of day passes and tournament passes sold.
Let's say "x" represents the number of day passes sold. Since the number of tournament passes sold is 32 more than the number of day passes sold, we can say the number of tournament passes sold is "x + 32".
Now, let's calculate the total value of tickets sold. Each day pass sells for $5, so the total value of the day passes sold is 5x. Each tournament pass sells for $10, so the total value of the tournament passes sold is 10(x + 32).
The given information states that the total value of tickets sold was $680. So we can set up the equation:
5x + 10(x + 32) = 680
Now, you can solve this equation to find the value of "x" (number of day passes sold).