Classify the equation as a conditional equation, an identity, or a contradiction and then state the solution.

24a+14=6(8a+3)-26a+4

24a+14=6(8a+3)-26a+4

24a+14 = 48a+18-26a+4
24a-48a+26a = 18+4-14
2a = 8
a = 4

a=4

To classify the equation and find the solution, we need to simplify it first. Let's start by distributing the terms on the right side of the equation:

24a + 14 = 6 * 8a + 6 * 3 - 26a + 4
24a + 14 = 48a + 18 - 26a + 4

Next, we can combine like terms:

24a + 14 = 22a + 22

Now, we can isolate the variable term (a) on one side of the equation. Let's subtract 22a from both sides:

24a - 22a + 14 = 22a - 22a + 22
2a + 14 = 22

Now, let's isolate the variable term on one side by subtracting 14 from both sides:

2a + 14 - 14 = 22 - 14
2a = 8

Finally, we can solve for a by dividing both sides of the equation by 2:

2a / 2 = 8 / 2
a = 4

Therefore, the solution to the equation 24a + 14 = 6(8a + 3) - 26a + 4 is a = 4.

To classify the equation and find the solution, we'll simplify the equation step by step.

First, let's distribute the terms on the right side:

24a + 14 = 6 * 8a + 6 * 3 - 26a + 4

Simplifying further:

24a + 14 = 48a + 18 - 26a + 4

Next, let's combine like terms:

24a + 14 = 48a - 26a + 18 + 4

Simplifying:

24a + 14 = 22a + 22

Now, let's isolate the variable term (a) on one side of the equation. Let's subtract 22a from both sides:

24a - 22a + 14 = 22a - 22a + 22

Simplifying further:

2a + 14 = 22

Next, let's isolate the constant term on one side by subtracting 14 from both sides:

2a + 14 - 14 = 22 - 14

Simplifying:

2a = 8

Finally, to solve for a, we divide both sides by 2:

(2a)/2 = 8/2

Simplifying:

a = 4

Now, let's classify the equation. Since a specific value of a (a = 4) satisfies the equation, we can say this equation is a conditional equation. The solution to the equation is a = 4.