In an experiment a mixture of oxygen and nitrogen gas is collected over water at 30'c and 700 torr pressure. What is the partial pressure of oxygen, if the partial pressure of nitrogen is 550 torr? (Vapour pressure of water at 30'c,4.2455kpa)
I would convert 4.255 kPa to torr first. Then
Ptotal = pO2 + pN2 + pH2O
Substitute and solve for pO2.
full answer
To find the partial pressure of oxygen in the collected gas mixture, we need to subtract the vapor pressure of water from the total pressure.
Given:
Total pressure (P_total) = 700 torr
Partial pressure of nitrogen (P_nitrogen) = 550 torr
Vapor pressure of water at 30°C = 4.2455 kPa (convert to torr)
First, let's convert the vapor pressure of water:
Vapor pressure of water at 30°C = 4.2455 kPa * 7.50062 torr/kPa ≈ 31.8391 torr
Next, we can calculate the partial pressure of oxygen:
Partial pressure of oxygen (P_oxygen) = P_total - P_nitrogen - Vapor pressure of water
P_oxygen = 700 torr - 550 torr - 31.8391 torr
P_oxygen ≈ 118.1609 torr
Therefore, the partial pressure of oxygen in the collected gas mixture is approximately 118.1609 torr.
To find the partial pressure of oxygen in the mixture, we need to subtract the vapor pressure of water from the total pressure of the gas collected over water.
First, let's convert the given vapor pressure from kPa to torr.
1 kPa = 7.50062 torr
So, the vapor pressure of water at 30°C is approximately:
4.2455 kPa * 7.50062 torr/kPa ≈ 31.84 torr
Given:
Total pressure of the gas collected over water = 700 torr
Partial pressure of nitrogen = 550 torr
Vapor pressure of water at 30°C = 31.84 torr
To find the partial pressure of oxygen, we can use the fact that the sum of the partial pressures of all the gases in a mixture is equal to the total pressure.
Partial pressure of oxygen + Partial pressure of nitrogen = Total pressure
Let's substitute the given values:
Partial pressure of oxygen + 550 torr = 700 torr
To find the partial pressure of oxygen, we solve for it by subtracting 550 torr from both sides of the equation:
Partial pressure of oxygen = 700 torr - 550 torr
Partial pressure of oxygen = 150 torr
Therefore, the partial pressure of oxygen in the mixture is 150 torr.