# College Algebra

The perimeter of a rectangle is
72 feet. The length of the rectangle is twice the width. Find the length and width of the rectangle.

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1. So if P=72ft , let's find an equation to compare! Perimeter=(Length x 2)+(width x 2) but we know that the length is twice the width or 2L=w , so let's substitute this back into our equation, P=(2L)(2w)=(2L)(2(2L))=8L^2=72
L^2=9
L=+-3 but it doesn't make sense to have a negative length so L must be 3. Plugging this back in, we get that 2L=w so w=6

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2. L = 2W

2L + 2W = 72
L + W = 36
2W + W = 36
3W = 36
W = 12 ----> L = 24

The rectangle is 24 ft long and 12 feet wide

check:
perimeter = 24+24+12+12 = 72

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