Classrooms on one side of the drama building are all numbered with consecutive even integers. If the first room, the room with the smallest classroom number, on this side of the building is numbered x, write an expression in x for the sum of the first five classroom numbers in a row. Then simplify this expression.
The sum of the first five classroom numbers in a row is _____.
so the numbers are two apart
x , x+2 , x+4 , etc.
add the 1st five
3x+6
Since the classrooms are numbered with consecutive even integers, the five classroom numbers in a row would be x, x+2, x+4, x+6, and x+8.
To find the sum of these five classroom numbers, we can simply add them together:
Sum = x + (x+2) + (x+4) + (x+6) + (x+8)
Simplifying this expression, we combine like terms:
Sum = 5x + 20
Therefore, the sum of the first five classroom numbers in a row is 5x + 20.
To find the sum of the first five classroom numbers in a row, we need to understand the pattern of the consecutive even integers.
Let's consider the first room numbered x. The next room will be x + 2, the room after that will be x + 4, and so on.
So, the five classroom numbers in a row will be:
x,
x + 2,
x + 4,
x + 6,
x + 8.
To find the sum of these five numbers, we can add them together:
x + (x + 2) + (x + 4) + (x + 6) + (x + 8).
Now, let's simplify this expression by combining like terms:
5x + (2 + 4 + 6 + 8).
Adding the numbers within the parentheses, we get:
5x + 20.
Therefore, the simplified expression for the sum of the first five classroom numbers in a row is 5x + 20.