Calculate the mass of oxygen which will be evolved on heating 5g of potassium Trioxochlorate (v)
KClO3
so for each mole of KClO3, you get 1.5 moles of O2
moles KClO3=5/123
moles O2= 1.5 times that
To calculate the mass of oxygen evolved on heating potassium trioxochlorate (V), we need to use stoichiometry and the molar ratios from the balanced chemical equation.
The balanced chemical equation for the reaction can be written as:
2KClO3(s) → 2KCl(s) + 3O2(g)
First, we need to determine the molar mass of potassium trioxochlorate (V) (KClO3):
Molar mass of KClO3 = (1 mol of K) + (1 mol of Cl) + (3 mol of O)
Molar mass of KClO3 = 39.1 g/mol + 35.5 g/mol + (3 * 16.00 g/mol)
Molar mass of KClO3 = 39.1 g/mol + 35.5 g/mol + 48.00 g/mol
Molar mass of KClO3 = 122.6 g/mol
Next, we need to calculate the number of moles of KClO3 by using the given mass:
Number of moles of KClO3 = Mass of KClO3 / Molar mass of KClO3
Number of moles of KClO3 = 5g / 122.6 g/mol
Number of moles of KClO3 ≈ 0.0408 mol
Based on the balanced chemical equation, we know that 2 moles of KClO3 produce 3 moles of O2. Therefore, we can set up a ratio:
2 moles of KClO3 : 3 moles of O2
0.0408 moles of KClO3 : x moles of O2
To find the number of moles of oxygen (O2) produced, we can use the ratio:
x = (3 moles of O2 / 2 moles of KClO3) * 0.0408 moles of KClO3
x ≈ 0.0612 moles of O2
Finally, we can calculate the mass of oxygen (O2) by multiplying the number of moles by the molar mass of oxygen:
Mass of O2 = Number of moles of O2 * Molar mass of O2
Mass of O2 = 0.0612 mol * 32.00 g/mol
Mass of O2 ≈ 1.96 g
Therefore, the mass of oxygen evolved on heating 5g of potassium trioxochlorate (V) is approximately 1.96 grams.