What volume of co2 has is produced when 20gm of 20/100 pure caco3 is completely heated

Solve the problem

Numerical problem

To determine the volume of CO2 produced when 20g of 20/100 pure CaCO3 is completely heated, we need to follow a few steps:

Step 1: Determine the molar mass of CaCO3.
The molar mass of CaCO3 can be calculated by adding the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms. The atomic masses are as follows:
Ca = 40.08 g/mol
C = 12.01 g/mol
O = 16.00 g/mol

Molar mass of CaCO3 = (40.08 g/mol) + (12.01 g/mol) + (16.00 g/mol x 3) = 100.09 g/mol

Step 2: Calculate the number of moles of CaCO3.
To find the number of moles, we use the formula: moles = mass / molar mass.
Number of moles of CaCO3 = 20g / 100.09 g/mol = 0.1999 mol (rounding to four decimal places)

Step 3: Determine the stoichiometry.
From the balanced chemical equation of the reaction:
CaCO3 (s) → CaO (s) + CO2 (g)
We can see that 1 mole of CaCO3 produces 1 mole of CO2.

Step 4: Calculate the volume of CO2 produced.
To find the volume of CO2, we can use the ideal gas law: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature (in Kelvin).

However, we need additional information, such as the temperature and pressure, to calculate the volume. Without this information, it is not possible to determine the exact volume of CO2 produced.

Therefore, to find the volume of CO2 produced when 20g of 20/100 pure CaCO3 is completely heated, you will need to know the temperature and pressure at which the reaction occurs.