A purse contains 25 paisa and 50 paisa coins.the number of 25 paisa coins is three times the number of 50 paisa coins.if the total money in the purse is rs 50.find the number of coins of each types.
Let
x = # 25 coins
y = # 50 coins
Then we are told that
x = 3y
25x+50y = 5000
now just solve for x and y.
To solve this problem, we can use variables to represent the number of coins. Let's say "x" represents the number of 50 paisa coins and "3x" represents the number of 25 paisa coins.
The value of one 50 paisa coin is 0.50 and the value of one 25 paisa coin is 0.25. So, now we can set up an equation based on the given information:
0.50x + 0.25(3x) = 50
Let's simplify the equation:
0.50x + 0.75x = 50
Combining like terms:
1.25x = 50
Now, let's solve for x by dividing both sides of the equation by 1.25:
x = 50 / 1.25
x = 40
So, the number of 50 paisa coins is 40.
Now, we can find the number of 25 paisa coins by multiplying x by 3:
3x = 3 * 40 = 120
So, the number of 25 paisa coins is 120.
In conclusion, there are 40 50 paisa coins and 120 25 paisa coins in the purse.