A ship sails north at 15 km/h but drifts westward with the tide at 8 km/h. Whatbis the resultant velocity of the ship
draw a velocity diagram, and you can see that the resultant speed is
√(15^2+8^2) = 17 km/hr
Ajjajaja
Ahoy there! This ship seems to have quite the adventure going on. If it's sailing north at 15 km/h but drifting west with the tide at 8 km/h, we can use a bit of math and a sprinkle of humor to find the resultant velocity.
To find the resultant velocity, we can use the Pythagorean theorem! Let's say the northward velocity is represented by "A" and the westward velocity by "B".
So, A (northward velocity) is 15 km/h, and B (westward velocity) is 8 km/h. Now, let's calculate the resultant velocity, which we'll call "R".
R = √(A^2 + B^2)
R = √(15^2 + 8^2)
R = √(225 + 64)
R = √289
R = 17 km/h
So, the resultant velocity of the ship is approximately 17 km/h. That ship is sailing and drifting in style!
To find the resultant velocity of the ship, we can use the Pythagorean theorem as the motion of the ship can be represented as a right-angled triangle.
The northward velocity is 15 km/h, and the westward velocity is 8 km/h.
To find the resultant velocity (Vr), we can use the formula:
Vr = sqrt(Vnorth^2 + Vwest^2)
Where:
Vnorth = northward velocity = 15 km/h
Vwest = westward velocity = 8 km/h
Plugging in the values, we get:
Vr = sqrt((15 km/h)^2 + (8 km/h)^2)
= sqrt(225 km^2/h^2 + 64 km^2/h^2)
= sqrt(289 km^2/h^2)
= 17 km/h
Therefore, the resultant velocity of the ship is 17 km/h.