Math

solve (v+6)^2 -40=0, where v is a real number.

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  1. (v+6)^2-40 = 0
    (v+6)^2 = 40
    v+6 = ±√40
    v = -6±√40
    or,
    v = -6±2√10

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  2. ( v + 6 )² - 40 = 0

    Add 40 to both sides

    ( v + 6 )² - 40 + 40 = 0 + 40

    ( v + 6 )² = 40

    v + 6 = ± √ 40

    v + 6 = ± √4 ∙ √10

    v + 6 = ± 2 √10

    Subtract 6 to both sides

    v + 6 - 6 = ± 2 √10 - 6 =

    ± 2 ( √10 - 3 )

    The solutions are:

    v₁ = - 2 √10 - 6 = - 2 ( √10 + 3 )

    v₂ = 2 √10 - 6 = 2 ( √10 - 3 )

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