Math

solve (v+6)^2 -40=0, where v is a real number.

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1. (v+6)^2-40 = 0
(v+6)^2 = 40
v+6 = ±√40
v = -6±√40
or,
v = -6±2√10

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2. ( v + 6 )² - 40 = 0

( v + 6 )² - 40 + 40 = 0 + 40

( v + 6 )² = 40

v + 6 = ± √ 40

v + 6 = ± √4 ∙ √10

v + 6 = ± 2 √10

Subtract 6 to both sides

v + 6 - 6 = ± 2 √10 - 6 =

± 2 ( √10 - 3 )

The solutions are:

v₁ = - 2 √10 - 6 = - 2 ( √10 + 3 )

v₂ = 2 √10 - 6 = 2 ( √10 - 3 )

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