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physics
A ski jumper leaves a slope at an angle of 20.0 degrees above the horizontal direction. She lands 3.50 seconds later at a point 20.0 meters below her takeoff point. (a) What was her initial speed? (b) How far does she travel
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A ski jump's velocity can be calculated (assume no friction). The tower is 60.0m high and the skier is at the bottom, who will leave the jump under a 21 degree angleto the horizontal, and land 33m below the starting point. The
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A car is traveling at a constant initial velocity of 100km/h on a level portion of road. It encounters a 6 percent incline (tan(theta)= 6/100) at point A and the car decelerates at a constant rate of gsin(theta). Find the speed of
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The Royal Gorge bridge over the Arkansas River is 310.0 m above the river. A 59.0kg bungee jumper has an elastic cord with an unstressed length of 62.0 m attached to her feet. Assume that, like an ideal spring, the cord is
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In the sport of pole vaulting, the jumper's point of mass concentration, called the centre of mass, must clear the pole. Assume that a 59 kg jumper must raise the centre of mass from 1.1 m off the ground to 4.6 m off the ground.
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A jumper of mass m=55 kg starts in a crouched position with the jumper's center of mass at a position y1=0 m. Just before the jumper leaves the floor, his or her center of mass is at y2=0.7 m. From another measurement, you have
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Boat A leaves point 1 for point 2 traveling at 52 mph. At the same time boat b leaves from point 2 to point 1 at 74 mph. Assume the distance from point 1 to point 2 is 882 miles. How long will it take them to meet? Give your
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if the tangent of two intersecting circles, at their points of intersection are perpendicular, the circles are said to be orthogonal. Show that the circles x^2+y^26x+4y+2=0 and x^2+y^2+8x+2y22=0 are orthogonal. find the equation
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A bungee jumper jumps from a bridge with a 3 m long bungee cord. Once the cord starts to stretch, it acts like an ideal spring with coefficient of elasticity k=100 N/m. What should be the minimum height of the bridge in m so that
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Consider the halfreactions: Cu^2+(aq) +2e^ ==> Cu(s) E naught = +0.34V Sn^2+(aq) + 2e^ ==> Sn E naught = 0.14V Fe^2+ + 2e^ ==> Fe(s) E naught = 0.44V Al^3+(aq) = 3e^ ==> Al(s) E naught = 1.66V Mg^2+(aq) = 2e^ ==> Mg(s) E
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